364 1) logo, 2x - 5 logo,2 x < -6;

1) $$log_{0.2}^2x - 5log_{0.2}x < -6$$
$$log_{0.2}x = t$$
$$t^2 - 5t < -6$$
$$t^2 - 5t + 6 < 0$$
$$D = 25 - 4 \cdot 6 = 1$$
$$t_1 = \frac{5 + 1}{2} = 3$$
$$t_2 = \frac{5 - 1}{2} = 2$$
$$2 < t < 3$$
$$2 < log_{0.2}x < 3$$
$$log_{0.2}0.04 < log_{0.2}x < log_{0.2}0.008$$
$$a = 0.2 < 1$$, значит знаки неравенства меняются.
$$0.008 < x < 0.04$$
Ответ: $$0.008 < x < 0.04$$