Решение:
- а) \( 27^{\frac{2}{3}} - 16^{\frac{1}{4}} - 64^{\frac{2}{3}} = (3^3)^{\frac{2}{3}} - (2^4)^{\frac{1}{4}} - (4^3)^{\frac{2}{3}} = 3^2 - 2^1 - 4^2 = 9 - 2 - 16 = 7 - 16 = -9 \)
- б) \( \frac{2}{3} \log_{2} \log_{3} 9 = \frac{2}{3} \log_{2} (2) = \frac{2}{3} \cdot 1 = \frac{2}{3} \)
Ответ: а) -9; б) \(\frac{2}{3}\).