Ответ:
Решение:
- a) \( \frac{4}{5} + \frac{2}{3} = \frac{4 \cdot 3}{5 \cdot 3} + \frac{2 \cdot 5}{3 \cdot 5} = \frac{12}{15} + \frac{10}{15} = \frac{22}{15} = 1\frac{7}{15} \)
- б) \( \frac{7}{8} - \frac{1}{12} = \frac{7 \cdot 3}{8 \cdot 3} - \frac{1 \cdot 2}{12 \cdot 2} = \frac{21}{24} - \frac{2}{24} = \frac{19}{24} \)
- в) \( \frac{3}{7} + 2\frac{2}{7} = \frac{3}{7} + \frac{16}{7} = \frac{19}{7} = 2\frac{5}{7} \)
- г) \( 5\frac{5}{14} - 1\frac{1}{21} = \frac{74}{14} - \frac{22}{21} = \frac{37}{7} - \frac{22}{21} = \frac{37 \cdot 3}{7 \cdot 3} - \frac{22}{21} = \frac{111}{21} - \frac{22}{21} = \frac{89}{21} = 4\frac{5}{21} \)
Ответ: a) \(\frac{22}{15}\) (или \(1\frac{7}{15}\)), б) \(\frac{19}{24}\), в) \(2\frac{5}{7}\), г) \(4\frac{5}{21}\).
