Ответ:
\(\ctg\alpha=\dfrac{\cos\alpha}{\sin\alpha}\):
\(\dfrac{\cos\alpha}{\sin\alpha}-\dfrac{\cos\alpha-1}{\sin\alpha}=\dfrac{1}{\sin\alpha}\).
Ответ: \(\dfrac{1}{\sin\alpha}\)
\(\ctg\alpha=\dfrac{\cos\alpha}{\sin\alpha}\):
\(\dfrac{\cos\alpha}{\sin\alpha}-\dfrac{\cos\alpha-1}{\sin\alpha}=\dfrac{1}{\sin\alpha}\).
Ответ: \(\dfrac{1}{\sin\alpha}\)