Вариант 1 1. Найти $$P_{10}^{1}$$ + $$C_{6}^{2}$$

1. $$P_{10}^{1}$$ + $$C_{6}^{2}$$ = 10 + $$\frac{6!}{2!(6-2)!}$$ = 10 + $$\frac{6!}{2!4!}$$ = 10 + $$\frac{6 \cdot 5 \cdot 4!}{2 \cdot 1 \cdot 4!}$$ = 10 + $$\frac{6 \cdot 5}{2}$$ = 10 + 15 = 25

Ответ: 25