Ответ:\(a+b+a^2-b^2=a+b+(a-b)(a+b)=(a+b)(a-b+1)\).\(9a^2-6ab+b^2-16=(3a-b)^2-4^2=(3a-b-4)(3a-b+4)\).\(x^3y^2-x^3-xy^2+x=x^3(y^2-1)-x(y^2-1)=(x^3-x)(y^2-1)=x(x-1)(x+1)(y-1)(y+1)\).\(1-x^2+4xy-4y^2=1-(x-2y)^2=(1-x+2y)(1+x-2y)\).