a) $$\frac{1}{8} \sqrt[6]{64} - 2 \sqrt[3]{-125} + \sqrt{1} = \frac{1}{8} \cdot 2 - 2 \cdot (-5) + 1 = \frac{1}{4} + 10 + 1 = 11\frac{1}{4} = 11,25$$;
б) $$\sqrt{121 \cdot 0,01} = \sqrt{1,21} = 1,1$$;
в) $$\frac{\sqrt{343}}{\sqrt{7}} = \sqrt{\frac{343}{7}} = \sqrt{49} = 7$$;
г) $$(\sqrt[5]{3})^{-10} = (3^{\frac{1}{5}})^{-10} = 3^{\frac{1}{5} \cdot (-10)} = 3^{-2} = \frac{1}{3^2} = \frac{1}{9}$$.
Ответ:
a) $$11,25$$;
б) $$1,1$$;
в) $$7$$;
г) $$\frac{1}{9}$$.