Найдем первообразную функции $$f(x) = cos(x) - \frac{1}{x^3}$$
$$F(x) = \int \left(cos(x) - \frac{1}{x^3}\right) dx = \int cos(x) dx - \int x^{-3} dx = sin(x) - \frac{x^{-3+1}}{-3+1} + C = sin(x) - \frac{x^{-2}}{-2} + C = sin(x) + \frac{1}{2x^2} + C$$.
Ответ: $$F(x) = sin(x) + \frac{1}{2x^2} + C$$