в) \frac{5}{c+3} - \frac{5c-2}{c^2+3c}.

в) \(\frac{5}{c+3} - \frac{5c-2}{c^2+3c}.\)

Приведем дроби к общему знаменателю \(c^2+3c = c(c+3)\)

\(\frac{5}{c+3} - \frac{5c-2}{c^2+3c} = \frac{5 \cdot c}{c(c+3)} - \frac{5c-2}{c(c+3)} = \frac{5c - 5c + 2}{c(c+3)} = \frac{2}{c(c+3)}\)

Ответ: \(\frac{2}{c(c+3)}\)