Решение:
- \( (6x^2 - 7x + 4) - (4x^2 - 4x + 18) = 6x^2 - 7x + 4 - 4x^2 + 4x - 18 = (6x^2 - 4x^2) + (-7x + 4x) + (4 - 18) = 2x^2 - 3x - 14 \)
- \( (3x + 9) + (-x^2 - 15x - 40) = 3x + 9 - x^2 - 15x - 40 = -x^2 + (3x - 15x) + (9 - 40) = -x^2 - 12x - 31 \)
- \( (10a^2 - 6a + 5) - (-11a + a^3 + 6) = 10a^2 - 6a + 5 + 11a - a^3 - 6 = -a^3 + 10a^2 + (-6a + 11a) + (5 - 6) = -a^3 + 10a^2 + 5a - 1 \)
- \( (13xy - 11x^2 + 10y^2) - (-15x^2 + 10xy - 15y^2) = 13xy - 11x^2 + 10y^2 + 15x^2 - 10xy + 15y^2 = (-11x^2 + 15x^2) + (13xy - 10xy) + (10y^2 + 15y^2) = 4x^2 + 3xy + 25y^2 \)
- \( (14ab^2 - 17ab + 5a^2b) + (20ab - 14a^2b) = 14ab^2 - 17ab + 5a^2b + 20ab - 14a^2b = 14ab^2 + (-17ab + 20ab) + (5a^2b - 14a^2b) = 14ab^2 + 3ab - 9a^2b \)
- \( \frac{7}{8} x^3y^2 - \frac{5}{6} xy^2 - \left( -\frac{7}{12} xy^2 + \frac{5}{12} x^3y^2 \right) = \frac{7}{8} x^3y^2 - \frac{5}{6} xy^2 + \frac{7}{12} xy^2 - \frac{5}{12} x^3y^2 \)
- \( = \left( \frac{7}{8} x^3y^2 - \frac{5}{12} x^3y^2 \right) + \left( -\frac{5}{6} xy^2 + \frac{7}{12} xy^2 \right) \)
- \( = \left( \frac{21}{24} x^3y^2 - \frac{10}{24} x^3y^2 \right) + \left( -\frac{10}{12} xy^2 + \frac{7}{12} xy^2 \right) \)
- \( = \frac{11}{24} x^3y^2 - \frac{3}{12} xy^2 = \frac{11}{24} x^3y^2 - \frac{1}{4} xy^2 \)
Ответ: 2x2 - 3x - 14; -x2 - 12x - 31; -a3 + 10a2 + 5a - 1; 4x2 + 3xy + 25y2; 14ab2 + 3ab - 9a2b; \( \frac{11}{24} x^3y^2 - \frac{1}{4} xy^2 \).