Ответ:\(5a+5b-am-bm=(a+b)(5-m)\).\(bm-mn-6+n=(b-n)(m-1)\).\(a^6+a^4-3a^2-3=(a^2+1)(a^4-3)\).\(10a^2b-2a^2+5ab^2-ab=a(2a+b)(5b-1)\).\(2x^3-3x^2y-4x+6y=(x^2-2)(2x-3y)\).\(x^2y-x+xy^2-y=(x+y)(xy-1)\).