1. Вычислите: 1) \(\frac{3}{9} \cdot \frac{2}{7}\); 2) \(\frac{7}{12} : \frac{7}{9}\); 3) \(\frac{7}{35} - \frac{1}{10}\)

Решение:

1. \(\frac{3}{9} \cdot \frac{2}{7} = \frac{3 \cdot 2}{9 \cdot 7} = \frac{6}{63} = \frac{2}{21}\)
2. \(\frac{7}{12} : \frac{7}{9} = \frac{7}{12} \cdot \frac{9}{7} = \frac{7 \cdot 9}{12 \cdot 7} = \frac{9}{12} = \frac{3}{4}\)
3. \(\frac{7}{35} - \frac{1}{10} = \frac{1}{5} - \frac{1}{10} = \frac{2}{10} - \frac{1}{10} = \frac{1}{10}\)

Ответ: 1) \(\frac{2}{21}\); 2) \(\frac{3}{4}\); 3) \(\frac{1}{10}\).