$$7^{3x} = \sqrt[5]{49}$$
$$7^{3x} = (7^2)^{\frac{1}{5}}$$
$$7^{3x} = 7^{\frac{2}{5}}$$
$$3x = \frac{2}{5}$$
$$x = \frac{2}{15}$$
Ответ: $$x = \frac{2}{15}$$