Решите уравнение: 1) $$3(x - 2) = x + 2$$; 2) $$5 - 2(x - 1) = 4 - x$$; 3) $$(7x + 1) - (9x + 3) = 5$$

Решение: 1) $$3(x - 2) = x + 2 \Rightarrow 3x - 6 = x + 2 \Rightarrow 3x - x = 2 + 6 \Rightarrow 2x = 8 \Rightarrow x = \frac{8}{2} \Rightarrow x = 4$$ 2) $$5 - 2(x - 1) = 4 - x \Rightarrow 5 - 2x + 2 = 4 - x \Rightarrow 7 - 2x = 4 - x \Rightarrow -2x + x = 4 - 7 \Rightarrow -x = -3 \Rightarrow x = 3$$ 3) $$(7x + 1) - (9x + 3) = 5 \Rightarrow 7x + 1 - 9x - 3 = 5 \Rightarrow -2x - 2 = 5 \Rightarrow -2x = 5 + 2 \Rightarrow -2x = 7 \Rightarrow x = -\frac{7}{2} \Rightarrow x = -3,5$$