2) (2-p)/(3-m) + (p^2-4)/(m^2-9) * (m+3)/(2-p).

2) $$(\frac{2-p}{3-m} + \frac{p^2-4}{m^2-9} \cdot \frac{m+3}{2-p}) = \frac{2-p}{3-m} + \frac{(p-2)(p+2)}{(m-3)(m+3)} \cdot \frac{m+3}{2-p} = \frac{2-p}{3-m} + \frac{-(2-p)(p+2)}{(m-3)(m+3)} \cdot \frac{m+3}{2-p} = \frac{2-p}{3-m} + \frac{-(p+2)}{m-3} = \frac{2-p}{3-m} + \frac{p+2}{3-m} = \frac{2-p + p+2}{3-m} = \frac{4}{3-m}$$.

Ответ: $$\frac{4}{3-m}$$