2. Найти значение производной в точке $$x_0 = \frac{\pi}{2}$$
$$y = \cos(x) + 2x^3$$
$$y' = -\sin(x) + 6x^2$$
$$y'(\frac{\pi}{2}) = -\sin(\frac{\pi}{2}) + 6(\frac{\pi}{2})^2 = -1 + 6\frac{\pi^2}{4} = -1 + \frac{3}{2}\pi^2$$
Ответ: $$y'(\frac{\pi}{2}) = -1 + \frac{3}{2}\pi^2$$