1. Найдем значения выражения:
$$arcsin(-\frac{1}{2}) - arccos(\frac{1}{2})$$
$$arcsin(-\frac{1}{2}) = -\frac{\pi}{6}$$
$$arccos(\frac{1}{2}) = \frac{\pi}{3}$$
$$arcsin(-\frac{1}{2}) - arccos(\frac{1}{2}) = -\frac{\pi}{6} - \frac{\pi}{3} = -\frac{\pi}{6} - \frac{2\pi}{6} = -\frac{3\pi}{6} = -\frac{\pi}{2}$$
Ответ: $$- \frac{\pi}{2}$$