1. Найдем значение выражения
$$arcsin(-\frac{1}{2})-arccos(\frac{1}{2})$$
$$arcsin(-\frac{1}{2})=-\frac{\pi}{6}$$
$$arccos(\frac{1}{2})=\frac{\pi}{3}$$
$$arcsin(-\frac{1}{2})-arccos(\frac{1}{2})=-\frac{\pi}{6}-\frac{\pi}{3}=-\frac{\pi}{6}-\frac{2\pi}{6}=-\frac{3\pi}{6}=-\frac{\pi}{2}$$
Ответ: $$\frac{-\pi}{2}$$