22. Найдите значения выражений: a) 7-\frac{1}{5}-8+\frac{3}{8}+9-\frac{3}{4}; г) 11\frac{3}{25}-2\frac{1}{4}-7\frac{7}{50}; б) 7\frac{11}{16}-6\frac{7}{8}+3\frac{3}{4}; д) 2\frac{13}{20}+4\frac{7}{40}-23\frac{8}{500}; в) 8\frac{21}{40}-5\frac{5}{8}+9\frac{3}{5}; e) 9\frac{9}{16}+3\frac{2}{5}-15\frac{123}{200};

Решим данные примеры:

1. a) $$7\frac{1}{5}-8+\frac{3}{8}+9-\frac{3}{4}=7+\frac{1}{5}-8+\frac{3}{8}+9-\frac{3}{4}=8+\frac{1}{5}+\frac{3}{8}-\frac{3}{4}=8+\frac{1\cdot8}{5\cdot8}+\frac{3\cdot5}{8\cdot5}-\frac{3\cdot10}{4\cdot10}=8+\frac{8}{40}+\frac{15}{40}-\frac{30}{40}=8-\frac{7}{40}=7\frac{40}{40}-\frac{7}{40}=7\frac{33}{40}$$
2. б) $$7\frac{11}{16}-6\frac{7}{8}+3\frac{3}{4}=7\frac{11}{16}-6\frac{14}{16}+3\frac{12}{16}=4+\frac{11-14+12}{16}=4+\frac{9}{16}=4\frac{9}{16}$$
3. в) $$8\frac{21}{40}-5\frac{5}{8}+9\frac{3}{5}=8\frac{21}{40}-5\frac{25}{40}+9\frac{24}{40}=12+\frac{21-25+24}{40}=12+\frac{20}{40}=12\frac{1}{2}$$
4. г) $$11\frac{3}{25}-2\frac{1}{4}-7\frac{7}{50}=11\frac{6}{50}-2\frac{12.5}{50}-7\frac{7}{50}=2+\frac{6-12.5-7}{50}=2-\frac{13.5}{50}=2-\frac{135}{500}=2-\frac{27}{100}=1\frac{100}{100}-\frac{27}{100}=1\frac{73}{100}$$
5. д) $$2\frac{13}{20}+4\frac{7}{40}-23\frac{8}{500}=2\frac{325}{500}+4\frac{87.5}{500}-23\frac{8}{500}=6+\frac{325+87.5-8}{500}=6+\frac{404.5}{500}=6+\frac{4045}{5000}=6+\frac{809}{1000}=6\frac{809}{1000}$$
6. e) $$9\frac{9}{16}+3\frac{2}{5}-15\frac{123}{200}=9\frac{1125}{2000}+3\frac{800}{2000}-15\frac{1230}{2000}=-3+\frac{1125+800-1230}{2000}=-3+\frac{695}{2000}=-3+\frac{139}{400}=-2\frac{400}{400}+\frac{139}{400}=-2\frac{261}{400}$$

Ответ: a) $$7\frac{33}{40}$$; б) $$4\frac{9}{16}$$; в) $$12\frac{1}{2}$$; г) $$1\frac{73}{100}$$; д) $$6\frac{809}{1000}$$; е) $$-2\frac{261}{400}$$.