Решение:
\[ \frac{2(4a^4)^3}{a^6 a^8} = \frac{2 \cdot 4^3 · (a^4)^3}{a^{6+8}} = \frac{2 \cdot 64 · a^{12}}{a^{14}} = \frac{128 · a^{12}}{a^{14}} \]
\[ \frac{128}{a^{14-12}} = \frac{128}{a^2} \]
\[ a^2 = (\sqrt{20})^2 = 20 \]
\[ \frac{128}{20} \]
\[ \frac{128 \div 4}{20 \div 4} = \frac{32}{5} \]
\[ \frac{32}{5} = 6.4 \]
Ответ: 6,4