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МатематикаВопрос:
10) (0,3h+...)² = ... + ... +25
Ответ:
The expression is of the form (a+b)², where a=0.3h and b²=25. Thus, b=5. (0.3h+5)² = (0.3h)² + 2(0.3h)(5) + 5² = 0.09h² + 3h + 25. The missing terms are 0.09h² and 3h.
Похожие
- 1) (a+2)²= a²+4a+4
- 2) (x+...)² = ... +6x+9
- 3) (y-...)² = ... - ... +25
- 4) (...-9)² = ... -18x+ ...
- 5) (... +8)² = b² + ... + ...
- 6) (a+...)² = ... +4ac+4c²
- 7) (c-...)² = ... - ... +25
- 8) (6+...)² = ... +12k+ ...
- 9) (...-...)² = 16 - ... +100s²
- 11) (15n+...)² = ... + ... +0,16
- 12) (...-2x)² = ... -12xt+ ...
- 13) (5-... )² = ... -10ab+ ...
- 14) (3np+...)² = ... +2np²+ ...
- 15) (1,3y-... )² = ... -0,2yz+ ...
- 16) (3y-...)² = ... - ... +16c²
- 17) (...+2m)² = 9k² + ... + ...
- 18) (...-...)² = 25b² - ... +4c²
- 19) (6p-...)² = ... -84pn+ ...
- 20) (4n+...)² = ... + ... +0,16q²
- 21) (...+0,2h)² = 25d² + ... + ...
- 22) (1/5 m - ...)² = ... - 2/35 m² + ...
- 23) (4/3 t³ + ...)² = ... + 8/3 t⁵h + ...
- 24) (7/3 x³ - ...)² = ... - 14/3 x³y + ...
- 25) (5/4 am³ - ...)² = ... - ... + 9/25 b⁸
- 26) (1,1bc³ - ...)² = ... + ... -2bc y²
- 27) (... -7kn⁵)² = ... + ... -42kn⁵t¹⁰
- 28) (... - ...)² = a⁶v² - ... +25z¹²
- 29) (xⁿ + ...)² = ... +10xⁿyᵐ +25 ...
- 30) (... + ...)² = 4x²ⁿ + ... +0,25b²
