Решение:
- 1) \( 36^{1/2} \cdot 125^{1/3} - 8^{1/3} = \sqrt{36} \cdot \sqrt[3]{125} - \sqrt[3]{8} = 6 \cdot 5 - 2 = 30 - 2 = 28 \).
- 2) \( \log_3 8 - \log_3 24 = \log_3 \frac{8}{24} = \log_3 \frac{1}{3} = -1 \).
- 3) \( \frac{\sqrt[3]{5}}{\sqrt[3]{625}} = \sqrt[3]{\frac{5}{625}} = \sqrt[3]{\frac{1}{125}} = \frac{1}{5} = 0.2 \).
- 4) \( 2\sin\frac{\pi}{6} + 4\cos\frac{\pi}{2} = 2 \cdot \frac{1}{2} + 4 \cdot 0 = 1 + 0 = 1 \).
Ответ: 1) 28; 2) -1; 3) 0.2; 4) 1.