№1. Выполните действия: a) 12-\frac{7}{12}-4-\frac{1}{8}-4\frac{1}{3}; б) 11-(4\frac{5}{6}+3\frac{3}{10}).

№1. Выполните действия:

a) $$12-\frac{7}{12}-4-\frac{1}{8}-4\frac{1}{3}=12-\frac{7}{12}-4-\frac{1}{8}-4-\frac{1}{3}=4-\frac{7}{12}-\frac{1}{8}-\frac{1}{3}=4-\frac{14}{24}-\frac{3}{24}-\frac{8}{24}=4-\frac{25}{24}=3\frac{24}{24}-\frac{25}{24}=3-\frac{1}{24}=2\frac{24}{24}-\frac{1}{24}=2\frac{23}{24}$$

б) $$11-(4\frac{5}{6}+3\frac{3}{10})=11-(4+\frac{5}{6}+3+\frac{3}{10})=11-(7+\frac{5}{6}+\frac{3}{10})=11-(7+\frac{25}{30}+\frac{9}{30})=11-(7+\frac{34}{30})=11-(7+1\frac{4}{30})=11-8\frac{4}{30}=3-\frac{4}{30}=2\frac{30}{30}-\frac{4}{30}=2\frac{26}{30}=2\frac{13}{15}$$

Ответ: a) $$2\frac{23}{24}$$; б) $$2\frac{13}{15}$$