$$3\frac{3}{8}+3\frac{1}{5}-4\frac{3}{12} - \frac{1}{6} = 3\frac{3}{8}+3\frac{1}{5}-4\frac{1}{4} - \frac{1}{6} = (3+3-4) + (\frac{3}{8} + \frac{1}{5} - \frac{1}{4} - \frac{1}{6}) = 2 + (\frac{3}{8} + \frac{1}{5} - \frac{1}{4} - \frac{1}{6}) = 2 + (\frac{45 + 24 - 30 - 20}{120}) = 2 + (\frac{69 - 50}{120}) = 2 + \frac{19}{120} = 2\frac{19}{120}$$
Ответ: $$2\frac{19}{120}$$