б) Выполним вычисления по действиям:
$$\frac{1}{2} - \frac{1}{3} = \frac{3}{6} - \frac{2}{6} = \frac{1}{6}$$
$$(\frac{1}{6})^3 = \frac{1^3}{6^3} = \frac{1}{216}$$
$$\frac{1}{3} - \frac{1}{4} = \frac{4}{12} - \frac{3}{12} = \frac{1}{12}$$
$$(\frac{1}{12})^2 = \frac{1^2}{12^2} = \frac{1}{144}$$
$$(\frac{3}{2})^2 = \frac{3^2}{2^2} = \frac{9}{4}$$
$$\frac{1}{216} : \frac{1}{144} = \frac{1}{216} \cdot \frac{144}{1} = \frac{144}{216} = \frac{2}{3}$$
$$\frac{2}{3} \cdot \frac{9}{4} = \frac{2 \cdot 9}{3 \cdot 4} = \frac{2 \cdot 3 \cdot 3}{3 \cdot 2 \cdot 2} = \frac{3}{2} = 1\frac{1}{2}$$
Ответ: $$1\frac{1}{2}$$