Решение:
- \(\sqrt{169} + \sqrt{25} = 13 + 5 = 18\)
- \(\sqrt{64 \cdot 9} = \sqrt{64} \cdot \sqrt{9} = 8 \cdot 3 = 24\)
- \(\sqrt{3 \cdot 18 \cdot 6} = \sqrt{3 \cdot (3 \cdot 6) \cdot 6} = \sqrt{3^2 \cdot 6^2} = 3 \cdot 6 = 18\)
- \(\sqrt{\frac{49}{121 \cdot 36}} = \frac{\sqrt{49}}{\sqrt{121 \cdot 36}} = \frac{7}{\sqrt{121} \cdot \sqrt{36}} = \frac{7}{11 \cdot 6} = \frac{7}{66}\)
Ответ: 1) 18; 2) 24; 3) 18; 4) \(\frac{7}{66}\).