a) $$\sqrt{144} + 5\sqrt{0.64} = 12 + 5 \cdot 0.8 = 12 + 4 = 16$$;
б) $$(4\sqrt{2})^2 = 16 \cdot 2 = 32$$;
в) $$\sqrt{0.16 \cdot 25} - 6 \sqrt{\frac{1}{36}} = \sqrt{\frac{16}{100} \cdot \frac{25}{1}} - 6 \cdot \frac{1}{6} = \sqrt{\frac{400}{100}} - 1 = \sqrt{4} - 1 = 2 - 1 = 1$$.
Ответ: a) 16; б) 32; в) 1