4. Упростите выражение: 1) 22m-\frac{7}{22}m; 2) 26+\frac{3}{8}x+\frac{13}{18}x; 3) \frac{1}{15}c-\frac{7}{24}c; 4) 3\frac{3}{6}y+2\frac{7}{16}y-\frac{4}{12}y.

1) $$22m-\frac{7}{22}m=(22-\frac{7}{22})m=(22-\frac{7}{22})m=\frac{22\cdot 22-7}{22}m=\frac{484-7}{22}m=\frac{477}{22}m=21\frac{15}{22}m$$ 2) $$26+\frac{3}{8}x+\frac{13}{18}x=26+(\frac{3}{8}+\frac{13}{18})x=26+(\frac{3\cdot 9+13\cdot 4}{72})x=26+(\frac{27+52}{72})x=26+\frac{79}{72}x=26+1\frac{7}{72}x$$ 3) $$\frac{1}{15}c-\frac{7}{24}c=(\frac{1}{15}-\frac{7}{24})c=(\frac{1\cdot 8-7\cdot 5}{120})c=(\frac{8-35}{120})c=-\frac{27}{120}c=-\frac{9}{40}c$$ 4) $$3\frac{3}{6}y+2\frac{7}{16}y-\frac{4}{12}y=3\frac{1}{2}y+2\frac{7}{16}y-\frac{1}{3}y=(3\frac{1}{2}+2\frac{7}{16}-\frac{1}{3})y=(\frac{7}{2}+\frac{39}{16}-\frac{1}{3})y=(\frac{7\cdot 24+39\cdot 3-1\cdot 16}{48})y=(\frac{168+117-16}{48})y=\frac{269}{48}y=5\frac{29}{48}y$$ Ответ: 1) 21$$\frac{15}{22}m$$; 2) 26+1$$\frac{7}{72}x$$; 3) -$$\frac{9}{40}c$$; 4) 5$$\frac{29}{48}y$$