$$ \left(-\frac{1}{4}x^5y^{13}\right)^2 \cdot 0.16x^7y = \left(\frac{1}{16}x^{10}y^{26}\right) \cdot 0.16x^7y = \frac{1}{16} \cdot 0.16 \cdot x^{10} \cdot x^7 \cdot y^{26} \cdot y = \frac{0.16}{16}x^{17}y^{27} = 0.01x^{17}y^{27}$$.
Ответ: $$0.01x^{17}y^{27}$$