\[ \left( \frac{x^2 - x}{2} + \frac{x}{3} \right) \times 6 = 0 \times 6 \]
\[ \frac{x^2 - x}{2} \times 6 + \frac{x}{3} \times 6 = 0 \] \[ (x^2 - x) \times 3 + x \times 2 = 0 \]\[ 3x^2 - 3x + 2x = 0 \]
\[ 3x^2 - x = 0 \]
\[ x(3x - 1) = 0 \]
\[ x = 0 \]
или\[ 3x - 1 = 0 \]
\[ 3x = 1 \] \[ x = \frac{1}{3} \]Ответ: 0