a) \(\frac{x}{4} = \frac{9}{x}\)
\(x^2 = 36\)
\(x = 6\) или \(x = -6\)
б) \(\frac{x}{4} = \frac{x}{9}\)
\(9x = 4x\)
\(5x = 0\)
\(x = 0\)
B) \(\frac{x}{6} = \frac{3x}{18}\)
\(18x = 18x\)
\(x \in R\)
г) \(\frac{x}{5} = \frac{3}{x}\)
\(x^2 = 15\)
\(x = \sqrt{15}\) или \(x = -\sqrt{15}\)
д) \(\frac{x}{x} = \frac{7}{x}\)
\(x = 7\)
Ответ: a) x = 6; x = -6; б) x = 0; в) x - любое число; г) \(x = \sqrt{15}\); \(x = -\sqrt{15}\); д) x = 7