$$44\frac{7}{15} \cdot 5\frac{15}{22}-5\frac{15}{22} \cdot 23\frac{16}{25} = 5\frac{15}{22} \cdot (44\frac{7}{15}-23\frac{16}{25}) = \frac{125}{22} \cdot (\frac{667}{15} - \frac{591}{25}) = \frac{125}{22} \cdot (\frac{667 \cdot 5 - 591 \cdot 3}{75}) = \frac{125}{22} \cdot (\frac{3335 - 1773}{75}) = \frac{125}{22} \cdot \frac{1562}{75} = \frac{25}{11} \cdot \frac{781}{15} = \frac{5}{11} \cdot \frac{781}{3} = \frac{3905}{33} = 118\frac{11}{33} = 118\frac{1}{3}$$
Ответ: $$118\frac{1}{3}$$