$$\frac{2\sqrt{7}}{\sqrt{7}+\sqrt{3}} + \frac{2\sqrt{3}}{\sqrt{7}-\sqrt{3}} = \frac{2\sqrt{7}(\sqrt{7}-\sqrt{3})+2\sqrt{3}(\sqrt{7}+\sqrt{3})}{(\sqrt{7}+\sqrt{3})(\sqrt{7}-\sqrt{3})} =$$
$$ = \frac{2\cdot7 - 2\sqrt{21} + 2\sqrt{21} + 2\cdot 3}{7-3} = \frac{14+6}{4} = \frac{20}{4} = 5$$
Ответ: 5