11. Найдите значение выражения $$\frac{1\frac{1}{4}+2\frac{1}{2}-\frac{1}{16}}{6\frac{1}{8}-1\frac{3}{8}+\frac{1}{12}} + \frac{6,24:0,3-15,8}{2,3\cdot 5+2,5}$$

$$\frac{1\frac{1}{4}+2\frac{1}{2}-\frac{1}{16}}{6\frac{1}{8}-1\frac{3}{8}+\frac{1}{12}} + \frac{6,24:0,3-15,8}{2,3\cdot 5+2,5} = \frac{\frac{5}{4}+\frac{5}{2}-\frac{1}{16}}{\frac{49}{8}-\frac{11}{8}+\frac{1}{12}} + \frac{20,8-15,8}{11,5+2,5} =$$

$$=\frac{\frac{20}{16}+\frac{40}{16}-\frac{1}{16}}{\frac{147}{24}-\frac{33}{24}+\frac{2}{24}} + \frac{5}{14} = \frac{\frac{59}{16}}{\frac{116}{24}} + \frac{5}{14} = \frac{59}{16} \cdot \frac{24}{116} + \frac{5}{14} = \frac{59 \cdot 24}{16 \cdot 116} + \frac{5}{14} = $$

$$=\frac{59 \cdot 3}{2 \cdot 116} + \frac{5}{14} = \frac{177}{232} + \frac{5}{14} = \frac{177 \cdot 7}{232 \cdot 7} + \frac{5 \cdot 116}{14 \cdot 116} = \frac{1239}{1624} + \frac{580}{1624} = \frac{1239+580}{1624} = \frac{1819}{1624} = 1\frac{195}{1624}$$

Ответ: $$1\frac{195}{1624}$$