Найдите сумму: a) $$4\frac{2}{9} + 3\frac{5}{18}$$ b) $$3\frac{5}{12} + 4\frac{7}{9}$$ v) $$7\frac{11}{12} + 1\frac{3}{8}$$ g) $$4\frac{3}{8} + 2\frac{4}{11}$$ d) $$6\frac{5}{11} + 5$$ e) $$7\frac{3}{7} + \frac{5}{21}$$ z) $$6 + 4\frac{2}{7}$$ z) $$\frac{3}{7} + 3\frac{4}{5}$$

Решение: a) $$4\frac{2}{9} + 3\frac{5}{18} = 4\frac{4}{18} + 3\frac{5}{18} = 7\frac{9}{18} = 7\frac{1}{2}$$ b) $$3\frac{5}{12} + 4\frac{7}{9} = 3\frac{15}{36} + 4\frac{28}{36} = 7\frac{43}{36} = 8\frac{7}{36}$$ v) $$7\frac{11}{12} + 1\frac{3}{8} = 7\frac{22}{24} + 1\frac{9}{24} = 8\frac{31}{24} = 9\frac{7}{24}$$ g) $$4\frac{3}{8} + 2\frac{4}{11} = 4\frac{33}{88} + 2\frac{32}{88} = 6\frac{65}{88}$$ d) $$6\frac{5}{11} + 5 = 11\frac{5}{11}$$ e) $$7\frac{3}{7} + \frac{5}{21} = 7\frac{9}{21} + \frac{5}{21} = 7\frac{14}{21} = 7\frac{2}{3}$$ z) $$6 + 4\frac{2}{7} = 10\frac{2}{7}$$ z) $$\frac{3}{7} + 3\frac{4}{5} = \frac{15}{35} + 3\frac{28}{35} = 3\frac{43}{35} = 4\frac{8}{35}$$ Ответ: a) $$7\frac{1}{2}$$ b) $$8\frac{7}{36}$$ v) $$9\frac{7}{24}$$ g) $$6\frac{65}{88}$$ d) $$11\frac{5}{11}$$ e) $$7\frac{2}{3}$$ z) $$10\frac{2}{7}$$ z) $$4\frac{8}{35}$$