Найдите сумму: 1) \(3\frac{7}{9}+5\frac{1}{6};\) 3) \(6\frac{8}{12}+9\frac{7}{18};\) 4) \(9\frac{3}{4}+4\frac{7}{8}+3\frac{5}{16}\)

Решим примеры:

1. $$3\frac{7}{9}+5\frac{1}{6} = 3 + 5 + \frac{7}{9} + \frac{1}{6} = 8 + \frac{7 \cdot 2 + 1 \cdot 3}{18} = 8 + \frac{14 + 3}{18} = 8 + \frac{17}{18} = 8\frac{17}{18}$$
2. $$6\frac{8}{12}+9\frac{7}{18} = 6 + 9 + \frac{8}{12} + \frac{7}{18} = 15 + \frac{8 \cdot 3 + 7 \cdot 2}{36} = 15 + \frac{24 + 14}{36} = 15 + \frac{38}{36} = 15 + 1\frac{2}{36} = 16\frac{1}{18}$$
3. $$9\frac{3}{4}+4\frac{7}{8}+3\frac{5}{16} = 9 + 4 + 3 + \frac{3}{4} + \frac{7}{8} + \frac{5}{16} = 16 + \frac{3 \cdot 4 + 7 \cdot 2 + 5}{16} = 16 + \frac{12 + 14 + 5}{16} = 16 + \frac{31}{16} = 16 + 1\frac{15}{16} = 17\frac{15}{16}$$

Ответ: 1) \(8\frac{17}{18}\); 3) \(16\frac{1}{18}\); 4) \(17\frac{15}{16}\)