5) \(\frac{5}{2}\)√44; 6) 2 \(\frac{3}{4}\) √\(6\frac{3}{4}\);

5) \(\frac{5}{2}\)√44 Разложим 44 на простые множители: \(44 = 4 * 11 = 2^2 * 11\) Тогда: \(\frac{5}{2}\)√44 = \(\frac{5}{2}\)\(\sqrt{2^2 * 11}\) = \(\frac{5}{2}\) * 2√11 = 5√11 6) 2 \(\frac{3}{4}\) √\(6\frac{3}{4}\) Переведем смешанные дроби в неправильные: 2 \(\frac{3}{4}\) = \(\frac{2 * 4 + 3}{4}\) = \(\frac{11}{4}\) \(6\frac{3}{4}\) = \(\frac{6 * 4 + 3}{4}\) = \(\frac{27}{4}\) Тогда: \(\frac{11}{4}\) √\(\frac{27}{4}\) = \(\frac{11}{4}\) * \(\frac{\sqrt{27}}{\sqrt{4}}\) = \(\frac{11}{4}\) * \(\frac{\sqrt{3^2 * 3}}{2}\) = \(\frac{11}{4}\) * \(\frac{3√3}{2}\) = \(\frac{33√3}{8}\)