65. Найдите значение выражения: 1) \(8\frac{1}{3}\cdot9-2\frac{2}{3}\cdot3\frac{1}{4}-4\frac{4}{7}\cdot3\frac{5}{24}\); 2) \(1\frac{1}{48}\cdot2\frac{2}{5}-\left(9\frac{1}{6}\cdot\frac{4}{15}+2\frac{5}{9}\right)\cdot\frac{1}{4}\).

1. \[8\frac{1}{3}\cdot9-2\frac{2}{3}\cdot3\frac{1}{4}-4\frac{4}{7}\cdot3\frac{5}{24}=\frac{25}{3}\cdot9-\frac{8}{3}\cdot\frac{13}{4}-\frac{32}{7}\cdot\frac{77}{24}.\] \[=75-\frac{26}{3}-\frac{44}{3}=75-\frac{70}{3}=\frac{155}{3}=51\frac{2}{3}.\]
2. \[1\frac{1}{48}\cdot2\frac{2}{5}-\left(9\frac{1}{6}\cdot\frac{4}{15}+2\frac{5}{9}\right)\cdot\frac14=\frac{49}{48}\cdot\frac{12}{5}-\left(\frac{55}{6}\cdot\frac{4}{15}+\frac{23}{9}\right)\cdot\frac14.\] \[=\frac{49}{20}-\left(\frac{22}{9}+\frac{23}{9}\right)\cdot\frac14=\frac{49}{20}-\frac54=\frac{6}{5}=1\frac15.\]

Ответ: 1) \(51\frac{2}{3}\); 2) \(1\frac{1}{5}\).