Решение:
\[ \frac{7}{22} : \frac{28}{33} = \frac{7}{22} \cdot \frac{33}{28} \]
\[ \frac{7}{22} \cdot \frac{33}{28} = \frac{7}{2 \cdot 11} \cdot \frac{3 \cdot 11}{4 \cdot 7} = \frac{3}{2 \cdot 4} = \frac{3}{8} \]
\[ \frac{19}{32} - \frac{3}{8} \]
\[ \frac{19}{32} - \frac{3 \cdot 4}{8 \cdot 4} = \frac{19}{32} - \frac{12}{32} = \frac{19 - 12}{32} = \frac{7}{32} \]
Ответ: \(\frac{7}{32}\)