3. Сократите дроби: а) \(\frac{10}{15}, \frac{12}{18}, \frac{24}{48}, \frac{28}{35}\); б) \(\frac{8\cdot11}{33\cdot4}\); в) \(\frac{18\cdot25}{75\cdot12}\); г) \(\frac{6\cdot7+7\cdot5}{49}\).

а) \(\frac{10}{15}=\frac23\); \(\frac{12}{18}=\frac23\); \(\frac{24}{48}=\frac12\); \(\frac{28}{35}=\frac45\).

б) \(\frac{8\cdot11}{33\cdot4}=\frac{2\cdot11}{33}=\frac{22}{33}=\frac23\).

в) \(\frac{18\cdot25}{75\cdot12}=\frac{18}{3\cdot12}=\frac{18}{36}=\frac12\).

г) \(\frac{6\cdot7+7\cdot5}{49}=\frac{42+35}{49}=\frac{77}{49}=\frac{11}{7}\).

Ответ: а) \(\frac23, \frac23, \frac12, \frac45\); б) \(\frac23\); в) \(\frac12\); г) \(\frac{11}{7}\).