\[ 7 \frac{1}{3} + 2 \frac{1}{4} = \frac{7 \cdot 3 + 1}{3} + \frac{2 \cdot 4 + 1}{4} = \frac{22}{3} + \frac{9}{4} \]
Приведём к общему знаменателю 12:
\[ \frac{22 \cdot 4}{3 \cdot 4} + \frac{9 \cdot 3}{4 \cdot 3} = \frac{88}{12} + \frac{27}{12} = \frac{115}{12} \]
\[ \frac{5}{6} \cdot \frac{115}{12} = \frac{5 \cdot 115}{6 \cdot 12} = \frac{575}{72} \]
\[ \frac{575}{72} : \frac{1}{4} = \frac{575}{72} \cdot 4 = \frac{575 \cdot 4}{72} = \frac{575}{18} \]
\[ 30 - \frac{575}{18} = \frac{30 \cdot 18}{18} - \frac{575}{18} = \frac{540}{18} - \frac{575}{18} = \frac{540 - 575}{18} = \frac{-35}{18} \]
Ответ: \( -1 \frac{17}{18} \)