Дано уравнение:
\[ 3 - \left(x + 1 \frac{1}{5}\right) = 1 \frac{3}{25} \]
\[ 1 \frac{1}{5} = \frac{1 \times 5 + 1}{5} = \frac{6}{5} \]
\[ 1 \frac{3}{25} = \frac{1 \times 25 + 3}{25} = \frac{28}{25} \]
\[ 3 - \left(x + \frac{6}{5}\right) = \frac{28}{25} \]
\[ x + \frac{6}{5} = 3 - \frac{28}{25} \]
\[ 3 = \frac{3 \times 25}{25} = \frac{75}{25} \]
\[ \frac{75}{25} - \frac{28}{25} = \frac{75 - 28}{25} = \frac{47}{25} \]
\[ x + \frac{6}{5} = \frac{47}{25} \]
\[ \frac{6}{5} = \frac{6 \times 5}{5 \times 5} = \frac{30}{25} \]
\[ x = \frac{47}{25} - \frac{30}{25} \]
\[ x = \frac{47 - 30}{25} = \frac{17}{25} \]
Ответ: \[ x = \frac{17}{25} \]