1) \(\frac{b^2}{2b-a} \cdot \left(2-\frac{a}{b}\right)\) 2) \(\frac{d^3}{c-3d} : \left(\frac{c}{d}-3\right)\) 3) \(\frac{5+3x}{x^5} : \left(\frac{3}{5} + \frac{1}{x}\right)\) 4) \(\frac{3+2y}{y^4} : \left(\frac{2}{3} + \frac{1}{y}\right)\)

Решение:

1. 1) \( \frac{b^2}{2b-a} \cdot \left(2-\frac{a}{b}\right) = \frac{b^2}{2b-a} \cdot \left(\frac{2b-a}{b}\right) = \frac{b^2 \cdot (2b-a)}{(2b-a) \cdot b} = b \)
2. 2) \( \frac{d^3}{c-3d} : \left(\frac{c}{d}-3\right) = \frac{d^3}{c-3d} : \left(\frac{c-3d}{d}\right) = \frac{d^3}{c-3d} \cdot \frac{d}{c-3d} = \frac{d^4}{(c-3d)^2} \)
3. 3) \( \frac{5+3x}{x^5} : \left(\frac{3}{5} + \frac{1}{x}\right) = \frac{5+3x}{x^5} : \left(\frac{3x+5}{5x}\right) = \frac{5+3x}{x^5} \cdot \frac{5x}{3x+5} = \frac{(5+3x)5x}{x^5(3x+5)} = \frac{5}{x^4} \)
4. 4) \( \frac{3+2y}{y^4} : \left(\frac{2}{3} + \frac{1}{y}\right) = \frac{3+2y}{y^4} : \left(\frac{2y+3}{3y}\right) = \frac{3+2y}{y^4} \cdot \frac{3y}{2y+3} = \frac{(3+2y)3y}{y^4(2y+3)} = \frac{3}{y^3} \)

Ответ: 1) \(b\); 2) \(\frac{d^4}{(c-3d)^2}\); 3) \(\frac{5}{x^4}\); 4) \(\frac{3}{y^3}\).