1.002. Вычислите: \(\left(\left(\frac79-\frac{47}{72}\right):1{,}25+\frac7{40}\right):(0{,}358-0{,}108)\cdot1{,}6-\frac{19}{25}\).

\(\frac79-\frac{47}{72}=\frac{56-47}{72}=\frac18\).

\(\frac18:1{,}25+\frac7{40}=\frac18:\frac54+\frac7{40}=\frac1{10}+\frac7{40}=\frac{11}{40}\).

\(0{,}358-0{,}108=0{,}25=\frac14\), поэтому \(\frac{11}{40}:\frac14\cdot1{,}6=\frac{11}{10}\cdot\frac85=\frac{44}{25}\).

\(\frac{44}{25}-\frac{19}{25}=1\).

Ответ: \(1\).