Выражение: (A ∨ ¬B ∧ ¬C) ∧ C
Заполним таблицу истинности:
¬B: Отрицание B.
¬C: Отрицание C.
¬B ∧ ¬C: Конъюнкция (логическое И) ¬B и ¬C.
A ∨ (¬B ∧ ¬C): Дизъюнкция (логическое ИЛИ) A и (¬B ∧ ¬C).
(A ∨ ¬B ∧ ¬C) ∧ C: Конъюнкция результата предыдущего шага и C.
<table border="1"> <thead> <tr> <th>A</th><th>B</th><th>C</th><th>¬B</th><th>¬C</th><th>¬B ∧ ¬C</th><th>A ∨ (¬B ∧ ¬C)</th><th>(A ∨ ¬B ∧ ¬C) ∧ C</th> </tr> </thead> <tbody> <tr> <td>0</td><td>0</td><td>0</td><td>1</td><td>1</td><td>1</td><td>1</td><td>0</td> </tr> <tr> <td>0</td><td>0</td><td>1</td><td>1</td><td>0</td><td>0</td><td>0</td><td>0</td> </tr> <tr> <td>0</td><td>1</td><td>0</td><td>0</td><td>1</td><td>0</td><td>0</td><td>0</td> </tr> <tr> <td>0</td><td>1</td><td>1</td><td>0</td><td>0</td><td>0</td><td>0</td><td>0</td> </tr> <tr> <td>1</td><td>0</td><td>0</td><td>1</td><td>1</td><td>1</td><td>1</td><td>0</td> </tr> <tr> <td>1</td><td>0</td><td>1</td><td>1</td><td>0</td><td>0</td><td>1</td><td>1</td> </tr> <tr> <td>1</td><td>1</td><td>0</td><td>0</td><td>1</td><td>0</td><td>1</td><td>0</td> </tr> <tr> <td>1</td><td>1</td><td>1</td><td>0</td><td>0</td><td>0</td><td>1</td><td>1</td> </tr> </tbody> </table>
Ответ:
<table border="1"> <thead> <tr> <th>A</th><th>B</th><th>C</th><th>(A ∨ ¬B ∧ ¬C) ∧ C</th> </tr> </thead> <tbody> <tr> <td>0</td><td>0</td><td>0</td><td>0</td> </tr> <tr> <td>0</td><td>0</td><td>1</td><td>0</td> </tr> <tr> <td>0</td><td>1</td><td>0</td><td>0</td> </tr> <tr> <td>0</td><td>1</td><td>1</td><td>0</td> </tr> <tr> <td>1</td><td>0</td><td>0</td><td>0</td> </tr> <tr> <td>1</td><td>0</td><td>1</td><td>1</td> </tr> <tr> <td>1</td><td>1</td><td>0</td><td>0</td> </tr> <tr> <td>1</td><td>1</td><td>1</td><td>1</td> </tr> </tbody> </table>