2) $$(4x+1)(2x-3)=(6x+1)(2x+3)-4x$$
$$8x^2 -12x +2x -3 = 12x^2 +18x +2x + 3 -4x$$
$$8x^2 -10x -3 = 12x^2 +16x + 3$$
$$0 = 4x^2 +26x +6$$
$$0 = 2x^2 +13x +3$$
$$D = 169 -4*2*3=169-24 = 145$$
$$x_1 = \frac{-13 +\sqrt{145}}{4}, x_2 = \frac{-13 -\sqrt{145}}{4}$$