We need to simplify \( i^{13} \). We know that the powers of \( i \) cycle with a period of 4:
To simplify \( i^{13} \), we divide the exponent by 4 and look at the remainder:
\( 13 \div 4 = 3 \) with a remainder of \( 1 \).
Therefore, \( i^{13} = i^1 \).
From the cycle of powers of \( i \), we know that \( i^1 = i \).
So, \( i^{13} = i \).
Now let's compare this with the given options:
The value \( i \) matches option 2.
Answer: 2. i