We need to simplify \( i^{11} \). We know that the powers of \( i \) cycle with a period of 4:
To simplify \( i^{11} \), we divide the exponent by 4 and look at the remainder:
\( 11 \div 4 = 2 \) with a remainder of \( 3 \).
Therefore, \( i^{11} = i^3 \).
From the cycle of powers of \( i \), we know that \( i^3 = -i \).
So, \( i^{11} = -i \).
Now let's compare this with the given options:
The value \( -i \) matches option 3.
Answer: 3. -i