Вопрос:

Выполните вычитание Вариант 2 1) \(\frac{7}{20} - \frac{11}{50} =\) 2) \(\frac{17}{33} - \frac{5}{22} =\) 3) \(\frac{9}{20} - \frac{5}{8} =\) 4) \(\frac{4}{7} - \frac{13}{28} =\) 5) \(\frac{5}{13} - \frac{14}{39} =\) 6) \(\frac{3}{8} - \frac{5}{12} =\) 7) \(\frac{3}{4} - \frac{5}{12} =\) 8) \(\frac{15}{23} - \frac{27}{46} =\) 9) \(\frac{9}{25} - \frac{14}{100} =\) 10) \(\frac{17}{35} - \frac{13}{28} =\)

Смотреть решения всех заданий с листа

Ответ:

Выполним вычитание дробей.

  1. \(\frac{7}{20} - \frac{11}{50} = \frac{7 \cdot 5}{20 \cdot 5} - \frac{11 \cdot 2}{50 \cdot 2} = \frac{35}{100} - \frac{22}{100} = \frac{35-22}{100} = \frac{13}{100}\)
  2. \(\frac{17}{33} - \frac{5}{22} = \frac{17 \cdot 2}{33 \cdot 2} - \frac{5 \cdot 3}{22 \cdot 3} = \frac{34}{66} - \frac{15}{66} = \frac{34-15}{66} = \frac{19}{66}\)
  3. \(\frac{9}{20} - \frac{5}{8} = \frac{9 \cdot 2}{20 \cdot 2} - \frac{5 \cdot 5}{8 \cdot 5} = \frac{18}{40} - \frac{25}{40} = \frac{18-25}{40} = -\frac{7}{40}\)
  4. \(\frac{4}{7} - \frac{13}{28} = \frac{4 \cdot 4}{7 \cdot 4} - \frac{13}{28} = \frac{16}{28} - \frac{13}{28} = \frac{16-13}{28} = \frac{3}{28}\)
  5. \(\frac{5}{13} - \frac{14}{39} = \frac{5 \cdot 3}{13 \cdot 3} - \frac{14}{39} = \frac{15}{39} - \frac{14}{39} = \frac{15-14}{39} = \frac{1}{39}\)
  6. \(\frac{3}{8} - \frac{5}{12} = \frac{3 \cdot 3}{8 \cdot 3} - \frac{5 \cdot 2}{12 \cdot 2} = \frac{9}{24} - \frac{10}{24} = \frac{9-10}{24} = -\frac{1}{24}\)
  7. \(\frac{3}{4} - \frac{5}{12} = \frac{3 \cdot 3}{4 \cdot 3} - \frac{5}{12} = \frac{9}{12} - \frac{5}{12} = \frac{9-5}{12} = \frac{4}{12} = \frac{1}{3}\)
  8. \(\frac{15}{23} - \frac{27}{46} = \frac{15 \cdot 2}{23 \cdot 2} - \frac{27}{46} = \frac{30}{46} - \frac{27}{46} = \frac{30-27}{46} = \frac{3}{46}\)
  9. \(\frac{9}{25} - \frac{14}{100} = \frac{9 \cdot 4}{25 \cdot 4} - \frac{14}{100} = \frac{36}{100} - \frac{14}{100} = \frac{36-14}{100} = \frac{22}{100} = \frac{11}{50}\)
  10. \(\frac{17}{35} - \frac{13}{28} = \frac{17 \cdot 4}{35 \cdot 4} - \frac{13 \cdot 5}{28 \cdot 5} = \frac{68}{140} - \frac{65}{140} = \frac{68-65}{140} = \frac{3}{140}\)

Ответ: смотри решение выше

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