б) $$\frac{a}{a+5} - \frac{a}{a-5} = \frac{a(a-5) - a(a+5)}{(a+5)(a-5)} = \frac{a^2 - 5a - a^2 - 5a}{a^2 - 25} = \frac{-10a}{a^2 - 25}$$